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Displaying 281-290 of 300 results.
IDPlCodelangPlGroupPlItemTitleCode 
 
173T-SQLDatum, ZeitZeitdifferenz--http://msdn.microsoft.com/de-de/library/ms189794.aspx SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000') AS SecondsView Update Delete
200JavaScriptDatum, ZeitAktuelles Datum/Uhrzeitdate = new Date(); // Sat Jun 14 2014 13:15:27 GMT+0200 (CEST) dateStringISO = date.toISOString(); // "2014-06-14T11:15:27.097Z" // Attention: Time is different because of the timezone date.toISOString().substring(0,10); //"2014-06-14" dateStringISO.split("T")[1]; // 11:15:27.097ZView Update Delete
205MySQLDatum, ZeitTagesnameSELECT DAYNAME(NOW()); -- Monday SELECT DAYNAME('2014-08-10'); -- Sunday -- To get localized names switch the parameter, e.g. to German SET lc_time_names = 'de_DE'; SELECT DAYNAME('2014-08-10'); -- SonntagView Update Delete
209SQLiteDatum, ZeitKalenderwoche eines Datums-- Standard Weeknumber function from SQLite: -- http://www.sqlite.org/lang_datefunc.html SELECT strftime('%W', '2014-08-25') -- The above calculation can lead to an wrong number if you expect an iso calendar week. -- Therefore better: -- http://stackoverflow.com/questions/15082584/sqlite-return-wrong-week-number-for-2013 SELECT (strftime('%j', date('2014-08-25', '-3 days', 'weekday 4')) - 1) / 7 + 1 AS ISOCalendarWeekNumber;View Update Delete
210T-SQLDatum, ZeitKalenderwoche eines Datumsselect DATEPART(ISO_WEEK,CAST('2014-08-25' AS DATE))View Update Delete
211SQLiteDatum, ZeitJahr aus Datum extrahierenSELECT strftime('%Y', '2014-08-25') AS Year;View Update Delete
212SQLiteDatum, ZeitTagesname-- There is no build in solution. Because of this you have to build a solution out of the weekday. -- Be careful, the first weekday (0) is a sunday SELECT ,CASE CAST(strftime('%w', myDateField) as integer) WHEN 0 then 'Sonntag' WHEN 1 then 'Montag' WHEN 2 then 'Dienstag' WHEN 3 then 'Mittwoch' WHEN 4 then 'Donnerstag' WHEN 5 then 'Freitag' WHEN 6 then 'Samstag' ELSE '????????????????????' END AS Tag_der_Woche_Deutsch ,CASE CAST(strftime('%w', myDateField) as integer) WHEN 0 then 'Sunday' WHEN 1 then 'Monday' WHEN 2 then 'Tuesday' WHEN 3 then 'Wednesday' WHEN 4 then 'Thursday' WHEN 5 then 'Friday' WHEN 6 then 'Saturday' ELSE '????????????????????' END AS Day_of_week_EnglishView Update Delete
216ORACLE PL/SQLDatum, ZeitAktuelles Datum/Uhrzeit-- if todays date is: 2014-02-02 then a static query would be SELECT TO_DATE('02/02/2014','dd/mm/yyyy') FROM dual -- system variable SELECT SYSDATE AS TODAY FROM SYS."DUAL"View Update Delete
230MySQLDatum, ZeitJahr aus Datum extrahierenSELECT extract(year from now()) AS Year; SELECT extract(year from '2014-01-01') AS Year; -- 2014View Update Delete
231MySQLDatum, ZeitMonat aus Datum extrahierenSELECT extract(month from now()) AS Month; SELECT extract(month from '2014-07-01') AS Month; -- 7View Update Delete